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1 year ago

13

X-3y=-24 5x+8y=-5 this equation is substitution, need help :))

1 answer:

Leto [7]1 year ago

6 0

Answer:

x=-9, y=5. (-9, 5).

Step-by-step explanation:

x-3y=-24

5x+8y=-5

--------------

x=-24+3y

5(-24+3y)+8y=-5

-120+15y+8y=-5

-120+23y=-5

23y=-5-(-120)

23y=-5+120

23y=115

y=115/23

y=5

x-3(5)=-24

x-15=-24

x=-24+15

x=-9

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Expand the expression 1/2(4t-10)

morpeh [17]

Hello there! Hope I can help!

$\mathrm{Multiply\:fractions}: \:a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c} \ \textgreater \ \frac{1\cdot \left(4t-10\right)}{2}$

$\mathrm{Apply\:rule}\:1\cdot \:a=a \ \textgreater \ \frac{4t-10}{2}$

$4t-10 \ \textgreater \ Rewrite \ \textgreater \ 2\cdot \:2t-2\cdot \:5 \ \textgreater \ \mathrm{Factor\:out\:common\:term\:}2$
$2\left(2t-5\right)$

$\frac{2\left(2t-5\right)}{2} \ \textgreater \ \mathrm{Divide\:the\:numbers:}\:\frac{2}{2}=1 \ \textgreater \ 2t-5$

Hope this helps!

6 0

1 year ago

Shear strength measurements for spot welds have been found to have standard deviation 1 0 pounds per square inch (psi). If 100 t

Temka [501]

Answer:

$P(\mu -1< \bar X$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Let X the random variable that represent the Shear strength of a population, and for this case we know the distribution for X is given by:

$X \sim N(\mu,10)$

Where $\mu$ and $\sigma=10$

And let $\bar X$ represent the sample mean, the distribution for the sample mean is given by:

$\bar X \sim N(\mu,\frac{\sigma}{\sqrt{n}})$

On this case $\bar X \sim N(\mu,\frac{10}{\sqrt{100}})$

We are interested on this probability

$P(\mu -1$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}$

If we apply this formula to our probability we got this:

$P(\mu -1$

$=P(\frac{\mu -1-\mu}{\frac{10}{\sqrt{100}}}$

And we can find this probability on this way:

$P(-1$

And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.

$P(-1$

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1 year ago

The ideal width of a certain conveyor belt for a manufacturing plant is 50 in. Conveyor belts can vary

Rom4ik [11]

Correct question is attached

Answer:

$\left[\begin{array}{ccc}x - 50\end{array}\right] \leq \frac{7}{32}$

$49\frac{25}{32}\leq x\geq 50\frac{7}{32}$

Step-by-step explanation:

Given.

The ideal width of a certain conveyor belt for a manufacturing plant is 50 in.

Conveyor belts can vary from the ideal width by at most 7/22 in.

Therefore, the absolute change in the width has to be less than or equal to 7/32 in.

If it will decrease than the the acceptable width for the conveyor belt is represented by the expression.

$\left[\begin{array}{ccc}x - 50\end{array}\right] \leq \frac{7}{32}$

The following equation is satisfy the given condition.

$\frac{-7}{32}\leq x-50\geq \frac{7}{32}$

$50-\frac{7}{32}\leq x\geq 50+\frac{7}{32}$

$49\frac{25}{32}\leq x\geq 50\frac{7}{32}$

Therefore, the correct choice is

$\left[\begin{array}{ccc}x - 50\end{array}\right] \leq \frac{7}{32}$

$49\frac{25}{32}\leq x\geq 50\frac{7}{32}$

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