Answer:
Step-by-step explanation:
The initial population of bacteria is 800 and we know that this number is quadrupling every hour.
<u>We're going to find a function in terms of t (time) that gives us the population of bacteria at that time.</u>
Since the population is quadrupling every hour the function in terms of t (where t is expressed in hours) is:
Now we need to find the time when there will be 5,120,000 bacterias. This means the time t when f(t) = 5,120,000
So we have 5,120,000 = 
Therefore, the time when there will be 5,120,000 bacterias will be:
Answer:
7.406
Step-by-step explanation:
It is 7.406 because 7x1 is 7, 4/10 is 0.4, and 6/1000 is 0.006. If you add those together, you will get 7.406.
To undo addition, you must subtract. Since we're subtracting 7 from one side, we must subtract 7 from the other side as well.
6x + 7 = 19
When we subtract 7, both sides are subtracting 7 to balance the equation.
6x = 12
Divide both sides by 6.
x = 2.
Hope this helps!
Answer:
11
Step-by-step explanation:
PC=QC=RC
3x+7=51-x
3x+x=51-7
4 x=44
x=11
Answer:
On the graphing calculator, use the function normCdf, where
- lower bound = -9999
- upper bound = 210
- mean = 250
- standard deviation = 46
It will result in normCdf(-9999,210,250,46) ≈ 0.192269 or 19.2269%
