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zloy xaker [14]
1 year ago
13

In kite JKLM , MJ=JK and ML=KL . Diagonals JL¯¯¯¯¯ and MK¯¯¯¯¯¯¯ intersect at point P, m∠MLK=48∘ , and m∠JKM=30∘ . What is m∠JML

?
Mathematics
1 answer:
Anna007 [38]1 year ago
7 0

Answer:

96°

Step-by-step explanation:

ΔKLM is isosceles, so base angle KML will be half the supplement of ∠MLK, or ...

.... ∠KML = (180° -48°)/2 = 66°

ΔKJM is also isosceles, so base angle JMK will be the same measure as ∠JKM, 30°.

∠JML = ∠JMK + ∠KML = 30° +66°

∠JML = 96°

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dmitriy555 [2]

To find the inverse, swap the x's with y's, the y's with x's, and solve for y.

y = 4x

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8 0
1 year ago
Find the value of x and fill in the table below.
GaryK [48]
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4 0
1 year ago
A certain forest covers an area of 3800 km^2. Suppose that each year this area decreases by 7.25%. What will the area be after 8
Levart [38]

Answer:

The area of forest after 8 years , decreases at the rate of 7.25% is 2081.108 square kilometers  .

Step-by-step explanation:

Given as :

The initial area of forest = 3800 square kilometer

The rate of decrease of area every year = r = 7.25 %

The time period for its decrease = t = 8 years

Let The forest area after 8 years = A square kilometers

Now, According to question

The forest area after 8 years = Initial area of forest × (1-\dfrac{\textrm rate}{100})^{\textrm time}

or, The forest area after 8 years = 3800 km² × (1-\dfrac{\textrm r}{100})^{\textrm t}

or, The forest area after 8 years = 3800 km² × (1-\dfrac{\textrm 7.25}{100})^{\textrm 8}

Or, The forest area after 8 years = 3800 km² × (0.9275)^{8}

Or, The forest area after 8 years = 3800 km² × 0.54766

Or, The forest area after 8 years = 2081.108 km²

So, Area of forest after 8 years = 2081.108 km²

Hence The area of forest after 8 years , decreases at the rate of 7.25% is 2081.108 square kilometers  . Answer

7 0
1 year ago
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MA_775_DIABLO [31]
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6 0
1 year ago
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HELPP <br> simplify.<br> (1-x/y) / ( 1-x^2/y^2) <br> 1. X/y<br> 2. 1/y+x<br> 3. Y/y+x
dezoksy [38]

Answer: y/y+x

Step-by-step explanation:

8 0
1 year ago
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